A Luchow is categorized under Family Practice Doctors in Tenafly, NJ .
| Business Name: | A Luchow |
| Contact Person: | Anya Luchow Liberman |
| Address: | 111 East Clinton Avenue, Tenafly, New Jersey 07670 |
| Phone Number: | (201) 569-4585 |
| Annual Revenue (USD): | $100.000 to $499.999 |
| Founding Year: | 2010 |
| Location Type: | Single Location |
| Employee Number: | 1 to 4 |
| Business Type: | B2C (Business to Consumer) |
| Business Category: | Family Practice Doctors |
| SIC Code: | 8011 |
| NAICS Code: | 621111 |
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The company A Luchow provides B2C services in the form of Family Practice Doctors from its single location in New Jersey. 1 to 4 employees work for A Luchow, and the business now earns $100.000 to $499.999 per annum.
A Luchow was launched in 2010 and is classified under SIC code and category 8011 , and NAICS number and grouping 621111 . To contact A Luchow, please call Anya Luchow Liberman with the phone number (201) 569-4585 or visit its single location at 111 East Clinton Avenue in Tenafly, New Jersey 07670.
The location of the single location can also be found using the coordinates 40.920325,-73.958737. Read more details about this business on the webpage or follow the company’s social media accounts, on Twitter and on Facebook.