| Business Name: |
Alexander Alan A MD |
| Contact Person: |
Alan Alexander |
| Address: |
400 North 17th St, Keokuk, Iowa 52632 |
| Phone Number: |
(319) 524-5734 |
| Annual Revenue (USD): |
$100.000 to $499.999 |
| Location Type: |
Single Location |
| Employee Number: |
1 to 4 |
| Business Type: |
B2C (Business to Consumer) |
| Business Category: |
Doctors |
| SIC Code: |
8011 |
| NAICS Code: |
6211110 |
| Share This Business: |
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The company Alexander Alan A MD provides B2C services in the form of Doctors from its single location in Iowa.
1 to 4 employees work for Alexander Alan A MD, and the business now earns $100.000 to $499.999 per annum.
Alexander Alan A MD was launched in 0 and is classified under SIC code and category 8011 , and NAICS number and grouping 6211110 .
To contact Alexander Alan A MD, please call Alan Alexander with the phone number (319) 524-5734 or visit its single location at 400 North 17th St in Keokuk, Iowa 52632.
The location of the single location can also be found using the coordinates 40.40793,-91.38872.
Read more details about this business on the webpage or follow the company’s social media accounts, on Twitter and on Facebook.